[Xerte] Re: sum part of array?

[Julian Tenney]

I did it like this so you can pass one param for sum from 0th to nth item, or n,m for the a sum of the range between n an m, or no params for sum of it all:

Array.prototype.sum = function(n,m) {
	if (arguments.length == 1){
		return this.slice(0,n).sum()
	} 
	if (arguments.length == 2){
		return this.slice(n,m).sum()
	}

	var sum = 0;
	for (var i = 0; i<this.length; i++) {
		sum += this[i];
	}
	return sum;
};

-----Original Message-----
From: xerte-bounces at lists.nottingham.ac.uk [mailto:xerte-bounces at lists.nottingham.ac.uk] On Behalf Of Julian Tenney
Sent: 26 July 2011 16:18
To: Xerte discussion list
Subject: [Xerte] Re: sum part of array?

myArray.slice(n,m).sum();

//test code/////////////////////////////////
Array.prototype.sum = function() {
	var sum = 0;
	for (var i = 0; i<this.length; i++) {
		sum += this[i];
	}
	return sum;
};

myArray = [0,1,2,3,4,5,6];

trace(myArray.slice(1,1).sum()); //n and m are 1 based, not zero??


-----Original Message-----
From: xerte-bounces at lists.nottingham.ac.uk [mailto:xerte-bounces at lists.nottingham.ac.uk] On Behalf Of Pat Lockley
Sent: 26 July 2011 15:30
To: Xerte discussion list
Subject: [Xerte] Re: sum part of array?

eval(array.join("+")) ?

On Tue, Jul 26, 2011 at 2:50 PM, Dave Burnett <d_b_burnett at hotmail.com> wrote:
>
>
> Just out of curiosity, is there any way to sum part of an array?
>
>
> [1,2,3,4,5]
>
>
> Lets say I have an index variable and I always will want to sum from 0 to
> that variable.
>
>
> pseudo
> my_array.sum(0,var);
>
>
> Or am I forced to loop + add?
>
>
> Or any elegant way to create a temp array of the target elements and sum on
> that instead?
>
>
> Dave
>
>
>
>
>
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