[Xerte] how to strip out a specific string?

[Dave Burnett]

I could be imagining things, but I thought Julian just posted something about Regular Expressions now being supported.

If that is true, then this would work:

new_xml = replace(original_xml, /the_string_here/g, "");

the /g at the end if the string parameter means "global", so it would replace all the instances of that URL with "".

Dave


From: ronm at mitchellmedia.co.uk
To: xerte at lists.nottingham.ac.uk
Subject: Re: [Xerte] how to strip out a specific string?
Date: Sun, 12 Apr 2009 20:19:55 +0100

Cheers Dave that's very helpful - I'll give that a try.
On 12 Apr 2009, at 19:35, Dave Burnett wrote:
It actually does have a closing tag: />

XML shorthands the closing tag to save characters when all the info is contained in the attributes, i.e. there is no actual value between the tags.

<name>jamesclay (James Clay)</name> //no attributes, data between tags


<link type="text/html" rel="alternate" href="http://twitter.com/jamesclay/statuses/1483252089"/>

//all data in opening tag attributes, no explicit closing tag, just />


So if you know the format you show below would be consistent, you could key on that "/>" as the end of the string and RFind (reverse find) back to the first "/" you hit.

That should isolate the actual picture name/format.

Dave


From: ronm at mitchellmedia.co.uk
To: xerte at lists.nottingham.ac.uk
Date: Sun, 12 Apr 2009 19:22:22 +0100
Subject: [Xerte] how to strip out a specific string?

Hi allI've been experimenting with the new module method of creating templates and have created a couple of new templates optimised for a specific purpose which I’ll happily share with the community once complete. One is an optimised  view of twitter feeds but unless I’m mistaken it seems like the xml isn't complete for some reason. I can pick up and display the text and links etc ok but I can't work out how to access the profile pics. Here's an example entry... <entry>    <id>tag:search.twitter.com,2005:1483252089</id>    <published>2009-04-09T12:59:26Z</published>    <link type="text/html" rel="alternate" href="http://twitter.com/jamesclay/statuses/1483252089"/>    <title>@ronm123 I meant in a browser, via a second projector probably.</title>    <content type="html">&lt;a href="http://twitter.com/ronm123"&gt;@ronm123&lt;/a&gt; I meant in a browser, via a second projector probably.</content>    <updated>2009-04-09T12:59:26Z</updated>    <link type="image/png" rel="image" href="http://s3.amazonaws.com/twitter_production/profile_images/96243182/Photo14_normal.jpg"/>    <twitter:source>&lt;a href="http://twitter.com/"&gt;web&lt;/a&gt;</twitter:source>    <author>      <name>jamesclay (James Clay)</name>      <uri>http://twitter.com/jamesclay</uri>    </author>  </entry> I want to be able to strip out the path to the .jpg e.g.http://s3.amazonaws.com/twitter_production/profile_images/96243182/Photo14_normal.jpg But can't work out how to do that. I can access the content of <id>,<title> and even <name> but the tag containing the profile pic link e.g. <link type=”image/png” doesn’t have a closing tag. Presumably I need some kind of function + regular expression - any suggestions? CheersRon
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